## Question

A particle moving with velocity equal to 0.4 *m/s* is subjected to an acceleration of* * 0.15 *m/s*^{2} for 2 sec in a direction at right angle to its direction of motion. What is the magnitude of resultant velocity?

### Solution

0.5 m/s

In vector from, 1^{st} equation of motion is

Here u = 0.4 m/s; a = 0.15 m/s^{2}; *t *= 2*s* and

#### SIMILAR QUESTIONS

If the initial velocity of the particle is u and collinear acceleration at any time *t* is at, calculate the velocity of the particle after time *t*.

A particle moves along a straight line such that its displacement at any time*t* is given by s = (*t ^{3}* + 6

*t*

^{2}+ 3

*t*+ 4)m. What is the velocity of the particle when its acceleration is zero?

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